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Written exam of 12th Jan 2019
.
Show that the following series converges
\[ β_{n=1}^β \left(\frac{1β 4β 7β 10 \cdots (3n-2)}{3β 6β 9 β 12 \cdots (3n)} \right)^ 2 \]
Solution
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Authors:
"Mennucci , Andrea C. G."
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convergence, of a series
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