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E15

[0GQ] Prerequisites:[06N],[06M],[06V].Difficulty:*.(Replaces 29W)

Let \((X,\tau )\) be a topological space. Consider the descending ordering between sets  1 , with this ordering \(𝜏\) is a directed set; we note that it has minimum, given by \(∅\).

Now suppose the topology is Hausdorff. Then taken \(x∈ A\), let \({{\mathcal U}}=\{ A∈𝜏: x∈ A\} \) be the family of the open sets that contain \(x\): show that \({{\mathcal U}}\) is a directed set; show that it has minimum if and only if the singleton \(\{ x\} \) is open (and in this case the minimum is \(\{ x\} \)). 2

Solution 1

[0GR]

By the exercise [06V], when \(\{ x\} \) is not open then \({{\mathcal U}}\) is a filtering set, and therefore can be used as a family of indices to define a nontrivial ”limit” (see Remark [237]). We will see applications in section [2B8].

  1. To formally reconnect to the definition seen in [06N] we define \(A ⪯ B \iff A⊇ B\) and associate the ordering \(⪯\) with \(𝜏\).
  2. Note that, the singleton \(\{ x\} \) is open iff \(x\) is an isolated point.
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This element replaces  29W
Bibliography
Book index
  • space, topological
  • topological space
  • order, directed, of sets
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