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E16

[0NH] Given (X,d) a metric space, show that d is continuous (as a function d:XΓ—X→ℝ). You can actually show that it is Lipschitz, by associating to XΓ—X the distance

d^(x,y)=d(x1,y1)+d(x2,y2), for x=(x1,x2),y=(y1,y2)∈XΓ—X .

Solution 1

[0NK]

[ [0NJ]]

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