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Exercise 3

[1YP] Show that every nβˆˆβ„• with nβ‰ 0 is successor of another kβˆˆβ„•, proving by induction on n this proposition

P(n)=.(n=0)∨(βˆƒkβˆˆβ„•,S(k)=n).

This shows that the successor function

S:ℕ→ℕ⧡{0}

is bijective.

If nβ‰ 0, we will call Sβˆ’1(n) the predecessor of n.

Solution 1

[22Q]

(Part of this result applies more generally, see [1Z1])

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