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Esercizio 28

[20Z]Note:Compitino del 26 gen 2016. Sia

\[ z_ n = \frac{1⋅ 3⋅ 5⋅ 7 \cdots (2n-1)}{2⋅ 4⋅ 6⋅8 \cdots ~ (2n)} \quad ; \]

Mostrate che \(\lim _{n→∞} z_ n=0\) ma

\[ ∑_{n=1}^∞ z_ n=∞ \quad . \]

Soluzione 1

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Authors: Ricci, Fulvio ; Pacini, Tommaso ; "Mennucci , Andrea C. G." .

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