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Exercise
14
[21H]Note:Taken from Rudin
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Prop.Β 3.41.
Let \((a_ n)_ n(b_ n)_ n,\) be sequences, let \(A_ n=β_{k=0}^ n a_ k\) and \(A_{-1}=0\), \(0β€ p β€ q\), then
\[ β_{n=p}^{q} a_ n b_ n = β_{n=p}^{q-1} A_ n (b_ n- b_{n+1}) + A_ q b_ q - A_{p-1} b_ p \quad . \]
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