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E0
[2GT]
Difficulty:*.
Fix
n
β
β
,
n
β₯
1
. Let
a
1
,
β¦
,
a
n
β
β
: then
π
π
π
β«
0
a
1
β«
0
a
2
β―
β«
0
a
n
cos
β‘
(
x
1
+
x
2
+
β―
x
n
)
d
x
1
d
x
2
β―
d
x
n
=
=
2
n
cos
β‘
(
β
i
=
1
n
a
i
2
)
β
i
=
1
n
sin
β‘
(
a
i
2
)
π
π
π
β«
0
a
1
β«
0
a
2
β―
β«
0
a
n
sin
β‘
(
x
1
+
x
2
+
β―
x
n
)
d
x
1
d
x
2
β―
d
x
n
=
=
2
n
sin
β‘
(
β
i
=
1
n
a
i
2
)
β
i
=
1
n
sin
β‘
(
a
i
2
)
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Authors:
"Mennucci , Andrea C. G."
.
Bibliography
Book index
Riemann integral
function, Riemann integrable ---
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