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E310

[05T]Let \(A,B,C\) sets, then

\begin{eqnarray*} A× (B∪ C) = (A× B)∪ (A× C)~ ~ ,\\ A× (B∩ C) = (A× B)∩ (A× C)~ ~ .\\ \end{eqnarray*}

Therefore the Cartesian product operation is distributive on the union and intersection.

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