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E10

[0YZ] Prerequisites:[0N1].Let KβŠ†X compact; fix 𝛼>1; define d~(x,y)=d(x,y)𝛼. We know from [0N1] that it is a distance. Show that

𝛼dim⁑(K,d)=dim⁑(K,d~)  .

In particular K=[0,1] (the interval KβŠ†X=ℝ) with the distance d~(x,y)=|xβˆ’y|𝛼 has dimension 𝛼.

Solution 1

[0Z0]

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