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E10

[0YZ] Prerequisites:[0N1].Let \(KโŠ† X\) compact; fix \(๐›ผ{\gt}1\); define \(\tilde d(x,y)=\sqrt[๐›ผ]{d(x,y)}\). We know from [0N1] that it is a distance. Show that

\[ ๐›ผ \dim (K,d)= \dim (K,\tilde d)~ ~ . \]

In particular \(K=[0,1]\) (the interval \(KโŠ† X=โ„\)) with the distance \(\tilde d(x,y)=\sqrt[๐›ผ]{|x-y|}\) has dimension \(๐›ผ\).

Solution 1

[0Z0]

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