EDB — 16J

Exercises

1. [16J] Given $L\in (0,1)$ if $f:ℝ\to ℝ$ satisfies

   $$|f(x)-f(y)|\le L|x-y|\forall x,y\in ℝ$$

   Then there is only one ”fixed point” that is a point $x$ for which $f(x)=x$.