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  1. [188] Topics:subdifferential.Prerequisites:[184].Difficulty:*.

    Let CβŠ†β„n be an open convex set, and f:C→ℝ a convex function; Given z∈C, we define the subdifferential βˆ‚f(z) as the set of v for which the relation [(14.24)] is valid (i.e., βˆ‚f(z) contains all vectors v defining the support planes to f in z).

    βˆ‚f(z) enjoys interesting properties.

    • βˆ‚f(z) is locally bounded: if z∈C and r>0 is such that B(z,2r)βŠ‚C, then L>0 exists such that βˆ€y∈B(z,r), βˆ€vβˆˆβˆ‚f(x) you have |v|≀L. In particular, for every z∈C, we have that βˆ‚f(z) is a bounded set.

    • Show that βˆ‚f is upper continuous in this sense: if z∈C and (zn)nβŠ‚C and vnβˆˆβˆ‚f(zn) and if znβ†’nz and vnβ†’nv then vβˆˆβˆ‚f(z). In particular, for every z∈C, βˆ‚f(z) is a closed set.

    Solution 1

    [189]

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Bibliography
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  • subdifferential
  • βˆ‚f , see subdifferential
  • convex function
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