Exercises
[188] Topics:subdifferential.Prerequisites:[184].Difficulty:*.
Let
be an open convex set, and a convex function; Given , we define the subdifferential as the set of for which the relation [(14.24)] is valid (i.e., contains all vectors defining the support planes to in ). enjoys interesting properties. is locally bounded: if and is such that , then exists such that , you have . In particular, for every , we have that is a bounded set.Show that
is upper continuous in this sense: if and and and if and then . In particular, for every , is a closed set.
Solution 1