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[194] Prove Young inequality: given \(a,b{\gt}0\) and \(p,q{\gt}1\) such that \(1/p + 1/q = 1\) then
\begin{equation} ab≤ \frac{a^ p} p+\frac{b^ q} q\label{eq:dis_ Young} \end{equation}
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with equality if and only if \(a^ p = b^ q\); prove this using concavity of the logarithm.
See also [1V7].
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