Exercises
[21X]Let \(kββ\) and let \(I=\{ 0,\ldots ,k\} \) with the usual ordering of \(β\): show that the concatenation of \(I\) with \(β\) has the same type of order as \(β\); while the concatenation of \(β\) with \(I\) does not have the same type of order.