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[28V](Solved on 2022-11-03) We fix the parameter \(m\), and we define recursively \((mΓ β )\) through
\( mΓ 0=0\)
\(β nβ β, mΓ (n+1)=mΓ n + m\);
[28V](Solved on 2022-11-03) We fix the parameter \(m\), and we define recursively \((mΓ β )\) through
\( mΓ 0=0\)
\(β nβ β, mΓ (n+1)=mΓ n + m\);