- E43
[2F3]Topics:perfect set.Prerequisites:[0QP],[2F2],[2FD].Difficulty:**.
Suppose \((X,d)\) is a complete metric space. A closed set \(E⊆ X\) without isolated points, i.e. consisting only of accumulation points, is called a perfect set.
Let \(C\) be the Cantor set. Assume that \(E\) is perfect and non-empty. Show that there exists a continuous function \(𝜑:C→ E\) that is an homeomorphism with its image. This implies that \(|E|≥ |ℝ|\).
So, in a sense, any non-empty perfect set contains a copy of the Cantor set.
This can be proven without relying on continuum hypothesis [2F2]. Cf. [0W3].
Due to [0J8], it is enough to show that there exists a \(𝜑:C→ E\) continuous and injective.
1
EDB — 2F3
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English
Authors:
"Mennucci , Andrea C. G."
.
Bibliography
Book index
Book index
- space, topological
- topological space
- accumulation point, in metric spaces
- topology, in metric spaces
- isolated point
- accumulation point
- set, perfect ---
- perfect
- continuum hypothesis
- continuum, cardinality of the —
- cardinality, of the continuum
- homeomorphism
- metric space
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