Exercises
[0ZY] Note that if \(v,wβ X\) are linearly dependent and have the same direction (i.e. you can write \(v=π w\) or \(w=π v\), for \(πβ₯ 0\)), then you have
\[ \| v+w\| = \| v\| +\| w\| \quad . \]In particular, a norm is not a strictly convex function, because
\[ \| \frac{v} 2+\frac{v} 2\| = \frac 1 2 \| v\| +\frac 1 2\| v\| \quad . \]